The perpendicular bisector of the line segment connecting the points \((-3,8)\)and \((-5,4)\) has an equation of the form \(y=mx+b\). Find \(m+b\).

Keihaku Nov 7, 2022

#1**-1 **

The equation of the line is y = -1/3*x + 5/3, so the answer is -1/3 + 5/3 = 4/3.

Guest Nov 7, 2022

#3**0 **

Answer: 16

Solution: m(gradient) = __y2-y1__

x2-x1

__8-4__ = __4__ = 2

-3--5 2

therefore m = **2**

Let's insert m into the equation y= mx+b

y=2x+b

8= 2(-3) + b

8=-6+b

8+6 = b

**14** = b

m+b= 2+14 = **16**

**THANKS!!!**

Emmajnr Nov 7, 2022