+0

Pls help! Give full answer pls!

0
190
7
+660

The perpendicular bisector of the line segment connecting the points \((-3,8)\)and \((-5,4)\) has an equation of the form \(y=mx+b\). Find \(m+b\).

Nov 7, 2022

#1
-1

The equation of the line is y = -1/3*x + 5/3, so the answer is -1/3 + 5/3 = 4/3.

Nov 7, 2022
#2
+660
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That is incorrect

Keihaku  Nov 7, 2022
#3
+11
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x2-x1

8-4    = 4 = 2

-3--5     2

therefore m = 2

Let's insert m into the equation y= mx+b

y=2x+b

8= 2(-3) + b

8=-6+b

8+6 = b

14 = b

m+b= 2+14 = 16

THANKS!!!

Nov 7, 2022
edited by Emmajnr  Nov 7, 2022
#4
+660
0

Keihaku  Nov 7, 2022
edited by Keihaku  Nov 7, 2022
#5
+33619
+1

Like so:

I'm sure you can add m and c!

Nov 8, 2022
#6
+660
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I added 8+(-1/2) and got 7.5 or 15/2 and it was still wrong... did I add the wrong numbers?!

Keihaku  Nov 9, 2022
#7
+33619
+1

Oops! My mistake.  c = 4 not 8, so y = -(1/2)x + 4

Make sure you check the details, don't just look at the answer!

Alan  Nov 10, 2022
edited by Alan  Nov 10, 2022