+660 The perpendicular bisector of the line segment connecting the points \((-3,8)\)and \((-5,4)\) has an equation of the form \(y=mx+b\). Find \(m+b\).
The equation of the line is y = -1/3*x + 5/3, so the answer is -1/3 + 5/3 = 4/3.
+11 Answer: 16
Solution: m(gradient) = y2-y1
x2-x1
8-4 = 4 = 2
-3--5 2
therefore m = 2
Let's insert m into the equation y= mx+b
y=2x+b
8= 2(-3) + b
8=-6+b
8+6 = b
14 = b
m+b= 2+14 = 16
THANKS!!!
