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0
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avatar+306 

The perpendicular bisector of the line segment connecting the points \((-3,8)\)and \((-5,4)\) has an equation of the form \(y=mx+b\). Find \(m+b\).

 Nov 7, 2022
 #1
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-1

The equation of the line is y = -1/3*x + 5/3, so the answer is -1/3 + 5/3 = 4/3.

 Nov 7, 2022
 #2
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That is incorrect

Keihaku  Nov 7, 2022
 #3
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Answer: 16

Solution: m(gradient) = y2-y1

                                      x2-x1

8-4    = 4 = 2

-3--5     2

therefore m = 2

Let's insert m into the equation y= mx+b

y=2x+b

8= 2(-3) + b

8=-6+b

8+6 = b

14 = b

m+b= 2+14 = 16

 

 

THANKS!!!

 Nov 7, 2022
edited by Emmajnr  Nov 7, 2022
 #4
avatar+306 
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That's also somehow incorrect...Can someone please give the correct answer?

Keihaku  Nov 7, 2022
edited by Keihaku  Nov 7, 2022
 #5
avatar+33270 
+1

Like so:

 

I'm sure you can add m and c!

 Nov 8, 2022
 #6
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I added 8+(-1/2) and got 7.5 or 15/2 and it was still wrong... did I add the wrong numbers?!

Keihaku  Nov 9, 2022
 #7
avatar+33270 
+1

Oops! My mistake.  c = 4 not 8, so y = -(1/2)x + 4

 

Make sure you check the details, don't just look at the answer!

Alan  Nov 10, 2022
edited by Alan  Nov 10, 2022

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