The diagonals of rectangle ABCD is 18 cm long and intersect in a 34 degree angle find the length and width of the rectangle
+2666 Using the equation:
\(\sin(34) = {x \over 18}\)
\(18 \times \sin(34) = x\)
Evaluating this, we find the height is \(\color{brown} \boxed{10.06547226}\)
Now, doing the same thing, but with \(\cos(34)\) instead, we find the width is \(\color{brown}\boxed{14.92267631}\)
Ask me if you have any questions!
+2666 Height is \(\sin(34) = {x \over 18}\)
Width is \(\cos(34) = {x \over 18}\)
