pls help me

Okay, let's do the first problem.

 

We know that the line passes through (2, 5) and has a slope of 4.

 

y = 4x + b

 

b=y-intercept

 

Now we just need to plug x (2) and y (5) in.

 

5 = 4(2) + b

 

5 = 8 + b

 

So... we can solve and see that

 

5 = 8 + (-3)

 

So.. the equation for the first problem is...

 

y=4x+(-3)

 

Now for the second problem.

 

We have two points, (-3, 1) and (-2, -1).

 

We need to find the slope first. Subtract the first equation's x from the second's, and the same for the ys. Then, put y over x.

 

-1-1=-2

 

-2-(-3)=1

 

The slope is -2.

 

Now, we have an equation of...

 

y = -2x + b

 

Let's do the same thing we did for the first problem and plug a point in. It doesn't matter which, so I'll use (-3, 1).

 

1 = -2 (-3) + b

 

1 = 6 + b

 

Again, we can solve for b.

 

1 = 6 + -5

 

Your equation is...

 

y = -2x + (-5)

 

In conclusion, the equations for the two problems are...

 

y = 4x + (-3)

 

and

 

y = -2x + (-5)