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# pls help me

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A tank holds 100 gallons of a thoroughly mixed solution which is 50% alcohol. Twenty-five gallons are drained from the tank and replaced with a solution that is 20% alchohol. The solution in the tank is thoroughly mixed. This procedure is repeated 2 more times. What percentage of the final solution is alcohol? Express your answer to the nearest whole number. Please help me and explain <3 ◕‿‿◕

Jun 16, 2021

#2
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In 100 gallons, alcohol = 50%

25 gallons is replaced with 20% alcohol

So, resulting sol $$=(75×{50\over 100})+(25×{20\over 100})$$

$$=37.5+5$$

$$=42.5$$% alcohol

The process is done again,

Resultant sol $$=(75×{42.5\over 100})+(25×{20\over 100})$$

$$=31.875+5$$

$$=36.875$$% alcohol

After the process is repeated again,

Resultant sol $$=(75×{36.875\over 100})+(25×{20\over 100})$$

$$=27.65625+5$$

$$=32.65625$$ $$=33$$% alcohol

∴The final solution has 33% alcohol

Jun 17, 2021

#1
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The percentage of the final solution which is alcohol is 28.

Jun 16, 2021
#2
+3

In 100 gallons, alcohol = 50%

25 gallons is replaced with 20% alcohol

So, resulting sol $$=(75×{50\over 100})+(25×{20\over 100})$$

$$=37.5+5$$

$$=42.5$$% alcohol

The process is done again,

Resultant sol $$=(75×{42.5\over 100})+(25×{20\over 100})$$

$$=31.875+5$$

$$=36.875$$% alcohol

After the process is repeated again,

Resultant sol $$=(75×{36.875\over 100})+(25×{20\over 100})$$

$$=27.65625+5$$

$$=32.65625$$ $$=33$$% alcohol

∴The final solution has 33% alcohol

amygdaleon305 Jun 17, 2021
#4
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Very nice  , amy   !!!!   CPhill  Jun 17, 2021
#5
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Thanks!! amygdaleon305  Jun 18, 2021