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this question is diffficult pls help me

this one is especially complicated

 Mar 3, 2018

Best Answer 

 #1
avatar+2340 
+1

#1)

 

Using the similarity statement, we can find \(YR\) by generating a proportion. 

 

\(\frac{DZ}{LZ}=\frac{MR}{YR}\) There are a few options here. This proportion is the one I chose to set up for this particular problem. Substitute in the known side lengths and solve for the missing one.
\(\frac{18}{21}=\frac{28.8}{YR}\) It is generally wise to simplify any fractions completely before one cross multiplies. Taking this precaution beforehand can ensure that the computation does not get out of hand.
\(\frac{6}{7}=\frac{28.8}{YR}\) Now we can cross multiply.
\(6YR=201.6\)  
\(YR=33.6\text{in}\) Do not forget the units!
\(YR=34\text{in}\) The question asks that the answer is rounded to the nearest whole inch, so I complied.

 

#2) 

 

This question becomes simple once you know the formula for the volume of a pyramid: \(V_{\text{pyramid}}=\frac{1}{3} lwh\)

 

\(V_{\text{pyramid}}=\frac{1}{3}lw h\) Of course, we must look at the given information; the figure is a square pyramid, so the side length of the bases is equivalent.
\(V_{\text{pyramid}}=\frac{1}{3}*183*183*110\) 183 is divisible by 3, so we can reduce that portion now.
\(V_{\text{pyramid}}=61*183*110\)  
\(V_{\text{pyramid}}=1227930\text{m}^3\)  
   

 

#3) 

 

The fill-in-the-blank questions are really just testing one's knowledge of the individual formulas. 

 

\(V_{\text{cylinder}}=\hspace{3mm}\pi r^2 h\\ V_{\text{cone}}\hspace{5mm}=\frac{1}{3} \pi r^2 h\)

 

When you place the formulas side by side, basic observation shows that a cone's formula is 1/3 of the volume of a cylinder with the same base and height. Of course, I already revealed what the formula is, so the volume of a cylinder is \(\pi r^2 h\) , and the formula for a cone is \(\frac{1}{3} \pi r^2 h\)

.
 Mar 3, 2018
 #1
avatar+2340 
+1
Best Answer

#1)

 

Using the similarity statement, we can find \(YR\) by generating a proportion. 

 

\(\frac{DZ}{LZ}=\frac{MR}{YR}\) There are a few options here. This proportion is the one I chose to set up for this particular problem. Substitute in the known side lengths and solve for the missing one.
\(\frac{18}{21}=\frac{28.8}{YR}\) It is generally wise to simplify any fractions completely before one cross multiplies. Taking this precaution beforehand can ensure that the computation does not get out of hand.
\(\frac{6}{7}=\frac{28.8}{YR}\) Now we can cross multiply.
\(6YR=201.6\)  
\(YR=33.6\text{in}\) Do not forget the units!
\(YR=34\text{in}\) The question asks that the answer is rounded to the nearest whole inch, so I complied.

 

#2) 

 

This question becomes simple once you know the formula for the volume of a pyramid: \(V_{\text{pyramid}}=\frac{1}{3} lwh\)

 

\(V_{\text{pyramid}}=\frac{1}{3}lw h\) Of course, we must look at the given information; the figure is a square pyramid, so the side length of the bases is equivalent.
\(V_{\text{pyramid}}=\frac{1}{3}*183*183*110\) 183 is divisible by 3, so we can reduce that portion now.
\(V_{\text{pyramid}}=61*183*110\)  
\(V_{\text{pyramid}}=1227930\text{m}^3\)  
   

 

#3) 

 

The fill-in-the-blank questions are really just testing one's knowledge of the individual formulas. 

 

\(V_{\text{cylinder}}=\hspace{3mm}\pi r^2 h\\ V_{\text{cone}}\hspace{5mm}=\frac{1}{3} \pi r^2 h\)

 

When you place the formulas side by side, basic observation shows that a cone's formula is 1/3 of the volume of a cylinder with the same base and height. Of course, I already revealed what the formula is, so the volume of a cylinder is \(\pi r^2 h\) , and the formula for a cone is \(\frac{1}{3} \pi r^2 h\)

TheXSquaredFactor Mar 3, 2018
 #2
avatar+532 
0

thx this is really helpful to my study 

cerenetie  Mar 4, 2018

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