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Suppose that $a$ and $b$ are positive real numbers, and let

\[f(x) =
\begin{cases}
\frac{a}{b}x & \text{ if }x\le-4, \\
abx^2 & \text{ if }x>-4.
\end{cases}
\]

If $f(-4)=-\frac{60}{13}$ and $f(4)=3120$, what is $a+b$?

 Mar 1, 2021
 #1
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0

a + b = 24.

 Mar 14, 2021

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