There boys donated the same amount of their savings to a charity organization. Radian donated 2/3 of his savings, Brandon donated 4/7 of his and Johnathan donated 3/5 of his. They had a total savings of $1652 at first. How much did each boy donate to the charity organization?

Guest Aug 27, 2021

#1**0 **

Three boys donated the same amount of their savings to a charity organization. Ramian donated 2/3 of his savings, Brandon donated 4/7 of his and Johnathan donated 3/5 of his. They had a total savings of $1652 at first. How much did each boy donate to the charity organization?

typo

Guest Aug 27, 2021

#2**0 **

Let, T

he savings of Ramlan be x,

Savings of Brandon be y,

Savings of Jonathan be z

Now in the question it is given that,

Ramian donated 2/3 of his savings,

Brandon donated 4/7 of his and

Johnathan donated 3/5 of his.

They had a total savings of $1652

Total savings = x + y + z = $1652

Also the donation made by all is given to be equal, hence we can write,

2/3(x)=4/7(y)=3/5(z)

Now we get,

2/3x = 4/7y

x/y = 6/7

similary,

x/z = 9/10

To simplify we shall take the ratio of savings of all three from above equation,

x : y : z = 18 : 21 : 20

Now let a be any constant, total saving is,

18a + 21a + 20a = 1692

59a = 1692

a = 28

Hence the donation by each is :

2/3(18)(28) = $336

4/7(21)(28) = $336

3/5(20)(28) = $336

Donation by each is $336.

KourageKowardlyDog Aug 28, 2021