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There boys donated the same amount of their savings to a charity organization. Radian donated 2/3 of his savings, Brandon donated 4/7 of his and Johnathan donated 3/5 of his. They had a total savings of $1652 at first. How much did each boy donate to the charity organization?

 Aug 27, 2021
 #1
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Three boys donated the same amount of their savings to a charity organization. Ramian donated 2/3 of his savings, Brandon donated 4/7 of his and Johnathan donated 3/5 of his. They had a total savings of $1652 at first. How much did each boy donate to the charity organization?

 

typo

 Aug 27, 2021
 #2
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Let, T 

he savings of Ramlan be x,

Savings of Brandon be y,

Savings of  Jonathan be z

 

 

 

Now in the question it is given that,

Ramian donated 2/3 of his savings,

Brandon donated 4/7 of his and

Johnathan donated 3/5 of his.

They had a total savings of $1652 

Total savings = x + y + z = $1652

Also the donation made by all is given to be equal, hence we can write,

                       2/3(x)=4/7(y)=3/5(z)
Now we get,

2/3x = 4/7y

x/y = 6/7

similary, 

                                 x/z = 9/10

 

 

 

To simplify we shall take the ratio of savings of all three from above equation,

                                         x : y : z = 18 : 21 : 20

Now let a be any constant, total saving is,

                  18a + 21a + 20a = 1692

                                      59a = 1692

                                          a = 28

 

 

 

 

Hence the donation by each is :

2/3(18)(28) = $336

4/7(21)(28) = $336

3/5(20)(28) = $336

 

Donation by each is $336.

 Aug 28, 2021

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