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A positive integer has exactly eight positive divisors. If two of the divisors are 21 and 35, what is the number? NOTE: For some integer n, a divisor of n is a non-zero integer that divides exactly into n leaving a remainder of 0. For example: 3 is a divisor of 18 since, 18 ÷ 3 = 6 remainder 0. 4 is not a divisor of 18, since 18 ÷ 4 = 4 remainder 2.

 Nov 3, 2017
 #1
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A positive integer has exactly eight positive divisors. If two of the divisors are 21 and 35, what is the number? NOTE: For some integer n, a divisor of n is a non-zero integer that divides exactly into n leaving a remainder of 0. For example: 3 is a divisor of 18 since, 18 ÷ 3 = 6 remainder 0. 4 is not a divisor of 18, since 18 ÷ 4 = 4 remainder 2.

 

lcm(21,35) = 105

 

laugh

 Nov 3, 2017
 #2
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Just in case you didn't understand heureka's answer !!!

 

105 =1 | 3 | 5 | 7 | 15 | 21 | 35 | 105 (8 divisors)

 Nov 3, 2017

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