1)Let theta be an acute angle such that sin(theta) = 3/5. What is the value of cos(180-theta)?
2)In triangle GHI we have GH = HI = 25 and GI = 30. What is sin angle GIH?
3)In triangle GHI we have GH = HI = 25 and GI = 30. What is sin angle GHI?
4)Let A be an acute angle such that sin4A = SinA. What is the measure of A in degrees?
5)In the diagram below, we know tan theta = 3/4. Find the area of the triangle.
Picture: https://latex.artofproblemsolving.com/1/5/b/15b2f668fb8720085a0232cba109b53f90a980d0.png
1)Let theta be an acute angle such that sin(theta) = 3/5. What is the value of cos(180-theta)?
Note...cos theta = 4/5
cos (180 - theta) =
cos (180) cos (theta) + sin (180) sin (theta) =
-cos (theta) + (0) * sin (theta) =
-cos (theta) =
- 4/5
2)In triangle GHI we have GH = HI = 25 and GI = 30. What is sin angle GIH?
H
25 25
G 30 I
The triangle is isosceles
Draw altitude HA.......this will bisect GI
And, using the Pythagorean Theorem,, HA = √[ HI^2 - (GI/2)^2 ] = √[ 25^2 - 15^2] = √400 = 20
So.....the sine of angle GIH = HA / HI = 20 / 25 = 4 / 5
5)In the diagram below, we know tan theta = 3/4. Find the area of the triangle.
If the tan = 3/4....then the sin = 3/5
So....the area of the triangle is
(1/2) (40) (60) sin (theta)
(1/2)(40)(60)(3/5) =
(3/10) (2400) =
720 units^2
4)Let A be an acute angle such that sin4A = SinA. What is the measure of A in degrees?
sin (4A) = sin A
sin ( 2 * 2A) = sin A
2sin 2A cos 2A = sin A
2 [ 2 sin A cos A ] * [ 2cos^2 - 1 ] = sin A
8sin A cos^3 A - 4sin A cos A - sin A = 0
sin A [ 8 cos^3 A - 4 cos A - 1 ] = 0
sin A = 0 ⇒ A = 0° [reject....A is > 0° ]
8cos^3 - 4cos A - 1 = 0 .... let cos A = x
8x^3 - 4x - 1 = 0
( 2x + 1) ( 4x^2 - 2x - 1 ) = 0
Setting the first factor to 0 and solving for x, we have that
x = -1/2 ⇒ cos A = -1/2 ⇒ A = 120° [reject....A is acute ]
Setting the second factor to 0 and solving for x, we have
4x^2 - 2x - 1 = 0
The solutions to this are :
x = [ 1 - √5 ] / 4 ⇒ cos A = [ 1 - √5] /4 ⇒ A = 108° [ reject....A is acute ]
x = [ 1 + √5 ] / 4 ⇒ cos A = [ 1 + √5 ] / 4 ⇒ A = 36°