pls help

ABC is an equilateral triangle with side length 6. Arcs are drawn centered at the vertices, connecting the midpoints of consecutive sides as shown. Find the area of the “triangular” region in the middle. 

That's too easy...  

The area of the middle region is      A = {[ sqrt ( 6² - 3² )] *3} - (3² pi / 2) 

                                                         A = 15.58845727 - 14.13716694

                                                         A = 1.451290329 u²