A right circular cone and a right circular cylinder each have a radius of 4 and a height of 3. Let A and B be the lateral surface areas of the cone and cylinder, respectively. Find A/B.
+128475 The slant height of the cone is sqrt [ 3^2 + 4^2] = sqrt [25] =5
And its lateral surface area is given by pi * radius * slant height =
pi * 4 * 5 =
20 pi [units^2] = A
The lateral surface are of the cylinder is given by
2pi * radius * height =
2pi * 4 * 3 =
24pi [units^2 ] = B
So
A/B = 20 pi / [24 pi] = 20 / 24 = 5/6
