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A right circular cone and a right circular cylinder each have a radius of 4 and a height of 3. Let  A and B be the lateral surface areas of the cone and cylinder, respectively. Find A/B.

Guest Oct 6, 2018
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The slant height of the cone  is  sqrt [ 3^2 + 4^2]  = sqrt [25]  =5

And its lateral surface area is given by pi * radius * slant height  =

pi * 4 * 5  =

20 pi   [units^2]   = A

 

The lateral surface are of the cylinder is given by

2pi * radius * height  =

2pi * 4 * 3  =

24pi  [units^2 ]  = B

 

So

 

A/B  =   20 pi / [24 pi]  =  20 / 24  =   5/6

 

 

cool cool cool

CPhill  Oct 6, 2018

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