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In how many ways can 3 identical red balls, 3 identical green balls, and 3 identical blue balls be arranged in a 3x3 grid, such that each row and each column of the grid contains 1 ball of each color?

 

 

thx

 Mar 8, 2021
 #1
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In first row, no. of color permutations = 3!

                                                           = 6

similarly for the next 2 rows = 2 * 6

                                             = 12

Thus, total no. of ways are 12.

 Mar 9, 2021

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