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# Pls Help!

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I went to my favorite taco stand with some friends. We ordered a total of 8 tacos and 3 burritos. John handed the cashier 3 dollars to help pay for the burritos, Tim gave her 2 dollars to help pay for the tacos, and then I gave her the rest of the money for the burritos and the rest of the money for the tacos. As I did this, I noticed that the ratio of the amount of money I paid for burritos to the amount of money I paid for tacos was 2:5. Later we went back to the same taco stand. This time we bought 10 tacos and 4 burritos. I paid for the whole thing by myself, and this time I spent 18 dollars more than I had last time. How much money did I spend this time?

Mar 18, 2019

#1
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Cost of tacos =   8t     cost of 3 burritos   = 3b

(3b-3) / (8t-2)  =   2/5

AND       10t + 4 b  =  18 +( 3b-3 +8t-2)        Now you have two equations with two unknowns...solve for  t = 4   b =5

10(4) + 4 (5) = \$60.00

Mar 18, 2019

#1
+2

Cost of tacos =   8t     cost of 3 burritos   = 3b

(3b-3) / (8t-2)  =   2/5

AND       10t + 4 b  =  18 +( 3b-3 +8t-2)        Now you have two equations with two unknowns...solve for  t = 4   b =5

10(4) + 4 (5) = \$60.00

ElectricPavlov Mar 18, 2019