Segment s1 has endpoints at (3+√2,5)and (4,7). Segment s2 has endpoints at (6−√2,3) and (3,5). Find the midpoint of the segment with endpoints at the midpoints of s1 and s2. Express your answer as (a,b).
use (x1+x22,y1+y22)
for (3+√2,5) and (4,7) :
(3+√2+42,5+72)
Ds1=(4.2,6)
for the 2nd one (6−√2,3) and (3,5)
(6−√2+32,3+52)
Ds2=(3.8,4)
so the coordinates of the midline are (4.2,6) and (3.8,4)
again doing the same thing:
(4.2+3.82,6+42)
Ds3(midline)=(4,5)