For what value of $n$ is $3\frac34-n=n+\frac12$? Express your answer as a common fraction.

1. Move the N on the left side to right, 3 3/4 = n + 1/2 +n

2. Subtract 1/2 from both sides, 3 1/4 = 2n

3. Divide by 2, 13/8

For what value of n is \(3\frac34-n=n+\frac12 \)? Express your answer as a common fraction.

Hello Guest!

\(3\dfrac34-n=n+\dfrac12\\ 2n=3 \dfrac{3}{4}-\dfrac{1}{2}=3\dfrac{1}{4}=\dfrac{26}{8}\\ \color{blue}n=\dfrac{13}{8}=1\dfrac{5}{8}\)

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