+20 Objects in elliptical orbits sweep out equal areas in equal times. This implies that the orbital speed of a planet around the Sun is not uniform – it moves fastest at the point closest to the Sun (known as the perihelion) and slowest at the point farthest away from the Sun (known as aphelion).
Pluto's Minimun orbital Velovity is 3.7km/sec. Determine values for Vaphelion and Vperihelion.
$${\mathtt{Da}} = {\mathtt{7\,375\,000\,000}} = \left({\mathtt{7.375}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{9}}}\right)$$
$${\mathtt{Dp}} = {\mathtt{4\,425\,000\,000}} = \left({\mathtt{4.425}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{9}}}\right)$$
$${\frac{{\mathtt{Va}}}{{\mathtt{Vp}}}} = {\frac{{\mathtt{Dp}}}{{\mathtt{Da}}}} = {\frac{{\mathtt{4\,425\,000\,000}}}{{\mathtt{7\,375\,000\,000}}}} = {\frac{\left({\mathtt{4.425}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{9}}}\right)}{\left({\mathtt{7.735}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{9}}}\right)}} = {\frac{{\mathtt{3}}}{{\mathtt{5}}}} = {\mathtt{0.6}}$$
$${\mathtt{Va}} = \left({\mathtt{0.6}}\right){\mathtt{\,\times\,}}{\mathtt{Vp}}$$
How do I solve for Vaphelion & Vpherihelion?
How do I solve for the velocity?
+394 The minimum velocity occurs at aphelion. This value (3.7Km/s) is stated in the question.
D_perihelion = 7.735E9Km
D_aphelion = 4.425E9Km
Orbital eccentricity is the ratio of P/A (perihelion/aphelion) values. (Either distance or velocity values).
Orbital eccentricity (P/A)= (7.735E9) / (4.425E9) = 1.66
The product of eccentricity and V_aphelion gives V_ perihelion.
(P/A)(Va)=Vp
(1.66)(3.7Km/s) = 6.14Km/s
_7UP_
+394 The minimum velocity occurs at aphelion. This value (3.7Km/s) is stated in the question.
D_perihelion = 7.735E9Km
D_aphelion = 4.425E9Km
Orbital eccentricity is the ratio of P/A (perihelion/aphelion) values. (Either distance or velocity values).
Orbital eccentricity (P/A)= (7.735E9) / (4.425E9) = 1.66
The product of eccentricity and V_aphelion gives V_ perihelion.
(P/A)(Va)=Vp
(1.66)(3.7Km/s) = 6.14Km/s
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