+0

# Plz help and you are poggers

0
49
4

For what real values of $$c$$ is $$4x^2+14x+c$$ the square of a binomial?

May 13, 2022

#1
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Taking the discriminant, we get c = 49.

May 13, 2022
#2
0

It' says it's wrong

Guest May 13, 2022
#3
+1810
+1

We know that the bionomial must be $$(2x + y)^2$$, that way the 2 2x's multiply out to $$4x^2$$

Expanding the bionomial out as is gives us: $$4x^2+2xy+2xy+y^2$$

We want the 2 2xy's to sum to 14x, so we have the equation: $$4xy= 14x$$. Solving for y, we find $$y = {7 \over2}$$

Now, we have to findsubsitute this in, and expand.

Hint: The co-efficent will be $$y^2$$

May 13, 2022
#4
0