+0  
 
0
69
5
avatar+90 

Here is the problem, please enter the answer in this forum

https://docs.google.com/presentation/d/1YIYm4ABMI-GvdhtrZYU6RehvvfRTRa8e3CP9ssSmpI4/edit?usp=sharing

 

 Apr 23, 2023
edited by Melody  Apr 23, 2023
 #1
avatar+90 
0

copy and paste the link in a new tab in your browser to see the problem.

 Apr 23, 2023
 #2
avatar
0

[APCB'QD] = 213 in2

 

[CQP] = 75 in2

 

[PRQ] = [B'CQ]

 

[ADRP] = [B'CP]

 

[B'CQ] =  30 in2

 

The area of triangle B'CQ is 30 square inches.

 Apr 23, 2023
 #3
avatar+90 
0

What is R? You are wrong. Thanks for trying!

 Apr 23, 2023
 #4
avatar
0

Since the paper was folded along CP, the area of triangle B'CQ is equal to the area of triangle BCP. Since P is located one-third of the way from A to B, the length of CP is 32​ the length of AB. Therefore, the area of triangle BCP is 1/2*1/3​⋅AB⋅CP=1/6*6AB⋅CP​. Since the total area covered by the folded paper is 213 square inches, the area of triangle BCP is 213−75=138 square inches. Therefore, the area of triangle B'CQ is 1/6​⋅138=23​ square inches.

 Apr 23, 2023
 #5
avatar+90 
0

Wrong again, thanks for trying.

 Apr 23, 2023

0 Online Users