The longer leg of a right triangle is $1$ foot shorter than twice the length of the shorter leg. The area of the triangle is $60$ square feet. What is the length of the hypotenuse, in feet?
so when the area of the triangle is 60 the 2 bases multiplied by each other equals 120 since 60*2 and we get the equation (2x^2-x)=120 and 2x^2=120+x so x=8 and 8*2-1=17 and 8^2+17^2=353 so the hypotenuse is \(\sqrt{353}\)
The longer leg of a right triangle is $1$ foot shorter than twice the length of the shorter leg. The area of the triangle is $60$ square feet. What is the length of the hypotenuse, in feet?
