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# Plz help im new here

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What is the correct equation for segment EF?

A. EF¯= (EG2)(GH2)

B. EF¯= (EG)(GH)

C. EF¯= (EG)(EH)

D. EF¯= (EG2)(FG2)

note:EF are line and all the anwser after equal sign are under a square root hope im clear

Jul 25, 2019

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(This question reminds me of this solution )

m∠EFH  =  m∠EGF   because they are both right angles

m∠FEH  =  m∠GEF   because they are the same angle

So by the AA similarity theorem,  △EFH ~ △EGF

EF / EH  =  EG / EF

Multiply both sides of the equation by  EF

EF2 / EH  =  EG

Multiply both sides of the equation by  EH

EF2  =  (EG)(EH)

Take the square root of both sides.

EF  = $$\sqrt{\text{(EG)(EH)}}$$

By the way, welcome to the forum!

Jul 25, 2019