Given \(f(x) = \frac{\sqrt{x-1}}{x-2}\), what is the smallest possible integer value for x such that f(x) has real number value?
The smallest postiive integer value of x is 5.
If x = 1, then f(1) = 0 is real
If x = 2 then the denominator is 0, so f(2) is undefined.
I wonder if you meant to say the smallest positive (rather than possible) integer, in which case
if x = 3 then f(3) = sqrt(2) which is real.
