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Given \(f(x) = \frac{\sqrt{x-1}}{x-2}\), what is the smallest possible integer value for x such that f(x) has real number value?

 Aug 24, 2020
 #1
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The smallest postiive integer value of x is 5.

 Aug 24, 2020
 #2
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If x = 1, then f(1) = 0 is real

If x = 2 then the denominator is 0, so f(2) is undefined.

I wonder if you meant to say the smallest positive (rather than possible) integer, in which case

if x = 3 then f(3) = sqrt(2) which is real.

 Aug 24, 2020

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