In a certain hyperbola, the center is at (2, 0), one focus is at (2, 6) and one vertex is at (2, -3). The equation of this hyperbola can be written as (y-k)^2/a^2-(x-h)^2/b^2=1.

Find h+k+a+b

Dahdahda Mar 20, 2019

#1**+2 **

In a certain hyperbola, the center is at (2, 0), one focus is at (2, 6) and one vertex is at (2, -3). The equation of this hyperbola can be written as

\(\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1 \)

Find h+k+a+b

Try looking at this:

https://www.youtube.com/watch?v=WU8k96qsA4E

Once you work it out you can check it by graphing in desmos.

Melody Mar 20, 2019