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# Plz help me fast

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In a certain hyperbola, the center is at (2, 0), one focus is at (2, 6)  and one vertex is at (2, -3). The equation of this hyperbola can be written as (y-k)^2/a^2-(x-h)^2/b^2=1.
Find h+k+a+b

Mar 20, 2019

#1
+100047
+2

In a certain hyperbola, the center is at (2, 0), one focus is at (2, 6)  and one vertex is at (2, -3). The equation of this hyperbola can be written as

$$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1$$

Find h+k+a+b

Try looking at this:

Once you work it out you can check it by graphing in desmos.

https://www.desmos.com/calculator

Mar 20, 2019
#2
+38
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I got it, thanks

Dahdahda  Mar 20, 2019