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In a certain hyperbola, the center is at (2, 0), one focus is at (2, 6)  and one vertex is at (2, -3). The equation of this hyperbola can be written as (y-k)^2/a^2-(x-h)^2/b^2=1.
Find h+k+a+b

 Mar 20, 2019
 #1
avatar+109744 
+2

In a certain hyperbola, the center is at (2, 0), one focus is at (2, 6)  and one vertex is at (2, -3). The equation of this hyperbola can be written as

 

\(\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1 \)


Find h+k+a+b

 

 

Try looking at this:  

https://www.youtube.com/watch?v=WU8k96qsA4E

 

Once you work it out you can check it by graphing in desmos.

https://www.desmos.com/calculator

 Mar 20, 2019
 #2
avatar+38 
+2

I got it, thanks

Dahdahda  Mar 20, 2019

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