+0  
 
0
573
4
avatar

The grid lines in the graph below are one unit apart. What is the equation of the circle plotted in the graph in standard form?

 

 Feb 23, 2021
 #1
avatar+1224 
0

The center of the circle is at (2, -4) and the radius of the circle is 4. We can write the equation like this and simplify.

 

\((x-2)^2 + (y+4)^2 = 16\)

 

\((x^2 - 4x + 4) + (y^2 + 8y + 16) = 16\)

 

\(x^2 - 4x + y^2 + 8y + 4 = 0\)

 Feb 23, 2021
 #2
avatar
0

Thank you so much! smiley

 Feb 23, 2021
 #3
avatar
0

its actually (x-2)^2+(y+3)^2=16 ... the center of the circle is at (2,-3) 

Guest Mar 3, 2021
 #4
avatar+21 
0

thx for letting me cheat on my aops test whoever posted these- xD

esgheasgyjjjjjuhga  Mar 3, 2021

0 Online Users