From the following infinite list of numbers, how many are integers? \(\sqrt{4096},\sqrt[3]{4096},\sqrt[4]{4096},\sqrt[5]{4096},\sqrt[6]{4096},\ldots \)
There are only four integers: $\sqrt{4096}$, $\sqrt[3]{4096}$, $\sqrt[4]{4096}$, and $\sqrt[6]{4096}$.
What about \(\sqrt[12]{4096}=2\) as well?
+136 
