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From the following infinite list of numbers, how many are integers? \(\sqrt{4096},\sqrt[3]{4096},\sqrt[4]{4096},\sqrt[5]{4096},\sqrt[6]{4096},\ldots \)

 Sep 18, 2021
 #1
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There are only four integers: $\sqrt{4096}$, $\sqrt[3]{4096}$, $\sqrt[4]{4096}$, and $\sqrt[6]{4096}$.

 Sep 18, 2021
 #2
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What about \(\sqrt[12]{4096}=2\) as well?

Alan  Sep 19, 2021

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