In triangle ABC, AB = 15, BC = 20, and AC = 20. Find the length of the shortest altitude in this triangle.
Acute isosceles triangle.
Sides: a = 15 b = 20 c = 20
Area: T = 139.054
Perimeter: p = 55
Semi-perimeter: s = 27.5
Angle ∠ A =44.049° = 44°2'55″ = 0.769 rad
Angle ∠ B =67.976° = 67°58'32″ = 1.186 rad
Angle ∠ C =67.976° = 67°58'32″ = 1.186 rad
Height: ha = 18.54
Height: hb = 13.905
Height: hc = 13.905 {You have 2 of them because it is an isosceles triangle}
