You are given that x is directly proportional to y^3, and is inversely proportional to √z. If the value of x is 3 when z is 12, what is the value of x when z is equal to 75? Express your answer as a common fraction. I NEED HELP! HARD
x = k y^3 /z1/2 not sure how to answer this unless we assume k y^3 is constant....which is what I'll do...
x = k / z1/2
3 = k /(121/2) k = 10.3923
Now when z = 75
x = 10.3923 / (751/2) = 1.2