+0

# PLZ HELP NEED HELP NOW

0
98
2

You are given that x is directly proportional to y^3, and  is inversely proportional to √z. If the value of x is 3 when z is 12, what is the value of x when z is equal to 75? Express your answer as a common fraction. I NEED HELP! HARD

THANK YOU

Mar 19, 2020

#1
+25776
+1

x = k y^3 /z1/2         not sure how to answer this unless we assume   k y^3  is constant....which is what I'll do...

x = k / z1/2

3 = k /(121/2)    k = 10.3923

Now when z = 75

x = 10.3923 / (751/2) =  1.2

Mar 19, 2020
edited by ElectricPavlov  Mar 19, 2020
edited by ElectricPavlov  Mar 19, 2020
edited by ElectricPavlov  Mar 19, 2020
#2
+4595
0

We have $$\frac{x}{y^3}$$ and $$x\sqrt{z}$$ are the two restrictions...

$$3\sqrt{12}=y*\sqrt{75}, y=\frac{6}{5}=1.2.$$

.
Mar 19, 2020