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You are given that x is directly proportional to y^3, and  is inversely proportional to √z. If the value of x is 3 when z is 12, what is the value of x when z is equal to 75? Express your answer as a common fraction. I NEED HELP! HARD

 

 

THANK YOU

 Mar 19, 2020
 #1
avatar+22085 
+1

x = k y^3 /z1/2         not sure how to answer this unless we assume   k y^3  is constant....which is what I'll do...

 

x = k / z1/2 

3 = k /(121/2)    k = 10.3923

 

Now when z = 75

 

x = 10.3923 / (751/2) =  1.2

 Mar 19, 2020
edited by ElectricPavlov  Mar 19, 2020
edited by ElectricPavlov  Mar 19, 2020
edited by ElectricPavlov  Mar 19, 2020
 #2
avatar+4496 
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We have \(\frac{x}{y^3}\) and \(x\sqrt{z}\) are the two restrictions...

 

\(3\sqrt{12}=y*\sqrt{75}, y=\frac{6}{5}=1.2.\)

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 Mar 19, 2020

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