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given thaTt x is acute and cos x=0.6 find tan x

 

given that sinx=0.3 find the angle x

 Oct 31, 2020
 #1
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sin^2 + cos^2 = 1

sin^2 = 1- .6^2

sin = + 0.8    (positive because angle is acute

 

tan = sin/cos =  .8/.6 = 1 1/3

 

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arcsin(.3) =    ......... o

 Oct 31, 2020
 #2
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sorry i am confused could you just explain in steps

 Oct 31, 2020
 #3
avatar+28021 
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sin^2 + cos^2 = 1     This is a trig IDENTITY you should know

 

acute angle means the angle is in Quadrant I    where   sin and cos are both positive.

 

There isn't any more steps.....can you be a little more precise as to what it is you do not understand?    ~EP

ElectricPavlov  Oct 31, 2020

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