given thaTt x is acute and cos x=0.6 find tan x
given that sinx=0.3 find the angle x
+37146 sin^2 + cos^2 = 1
sin^2 = 1- .6^2
sin = + 0.8 (positive because angle is acute
tan = sin/cos = .8/.6 = 1 1/3
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arcsin(.3) = ......... o
+37146 sin^2 + cos^2 = 1 This is a trig IDENTITY you should know
acute angle means the angle is in Quadrant I where sin and cos are both positive.
There isn't any more steps.....can you be a little more precise as to what it is you do not understand? ~EP
