+4622 If we express \($x^2 + 4x + 5$\) in the form \(a(x - h)^2 + k\) , then what is \(h\) ?
+956 I'm not sure what you mean by dollars, but I'll treat that as nothing.
x^2+4x+5 --> h would be the x value of the vertex
To find the vertex we need to you the formula: -b/2a
This formula is for the axis of symmetry, but the axis of symmetry is also the x value of the vertex.
Lets state our letters:
a=1
b=4
c=5
Plug and chug into the formula
-4/2(1)
-4/2=
-2. So h =-2
Now lets find a and k
a is our strech factor which is in front of our x^2.
So a is =1
Now to find our k value which is the y value of the vertex, we plug in our x value for everytime we see x
(-2)^2+4(2)+5
4+8+5
=17 so the k=17
Now lets plug into our vertex formula
a=1, h=-2 and k=17
y=a(x-h)^2+k
NOTE for our x value of our vertex which is h we flip signs when we put it into the formula
So: y=(x+2)^2+17
Hope that helps
