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The amount of money a certain company has can be modeled with the line y=-265x+2800, where x is the number of workers the company decides to hire. What is the maximum number of workers the company can hire before the company has no money left and goes bankrupt?

 Mar 14, 2019

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 y=-265x+2800

 

The company will have no money when y =  0.....so

 

0 = -265x + 2800      subtract 2800 from both sides

 

-2800 = - 265x      divide both sides by -265

 

≈10.56  = x

 

So....they can hire a max of 10 workers and still remain solvent....(the 11th worker will sink them )

 

cool cool cool

 Mar 14, 2019

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