web2.0calc
 
+0  
 

 Plz help, thank you

0
1229
1
avatar+150 

The amount of money a certain company has can be modeled with the line y=-265x+2800, where x is the number of workers the company decides to hire. What is the maximum number of workers the company can hire before the company has no money left and goes bankrupt?

 Mar 14, 2019

1+0 Answers

 #1
avatar+128408 
0

 y=-265x+2800

 

The company will have no money when y =  0.....so

 

0 = -265x + 2800      subtract 2800 from both sides

 

-2800 = - 265x      divide both sides by -265

 

≈10.56  = x

 

So....they can hire a max of 10 workers and still remain solvent....(the 11th worker will sink them )

 

cool cool cool

 Mar 14, 2019

4 Online Users

avatar

Top Users

avatar+128408 CPhill moderator
avatar+118608 Melody moderator
avatar+33615 Alan moderator
avatar+14905 asinus moderator
avatar+9519 MaxWong
avatar+3144 admin administrator
avatar+2440 GingerAle
avatar+1763 tomtom
avatar+1484 bader
avatar+1037 parmen
avatar+1030 blackpanther

Sticky Topics