+0  
 
0
320
3
avatar+644 

What is the area, in square units, of the interior region formed by the lines y = 2x - 4, y = -3x +16 and the y-axis?

waffles  Nov 21, 2017
edited by waffles  Nov 21, 2017
 #1
avatar+91162 
+1

I'm assuming that you mean the x axis

 

We have a triangular area...

 

The line y  = 2x - 4    and y =  -3x + 16  intersect at the x value

 

2x - 4   =  -3x + 16

5x  =  20

x =4

So...x =  2(4) - 4  =  4

 

And the y coordinate is  2(4) - 4  = 4....and thid the height of the triangular aresw

 

And   y = 2x - 4   intersects the x axis at x =  2  

And y = -3x + 16   intersects the x axis at  16/3

 

So....we have a triangle with a base of  [ 16/3 - 2]   = 10/3    and a height of 4

 

So....the area is     (1/2)(10/3) (4)   =  20/3 units^2

 

 

cool cool cool

CPhill  Nov 21, 2017
 #2
avatar+644 
0

i made a edit

waffles  Nov 21, 2017
 #3
avatar+91162 
+1

OK....

 

We have a  triangle with a height of 4 and a base of 20

 

So....the area is  (1/2)(20)(4)  =  40 units^2

 

Here's the graph : https://www.desmos.com/calculator/ktl6nn6onh

 

cool cool cool

CPhill  Nov 21, 2017

13 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.