11x-4(ax-9) is identical to b(x+2)-2

where a and b are intergers

work out the values of a and b

Guest Apr 14, 2022

#2**+1 **

Expand both equations and set them equal to each other: \(11x - 4ax + 36 = bx+2b-2\)

Subtract 2 from both sides: \(11x-4ax+38=bx+2b\)

We want them to be identical, so \(2b = 38\), and \(\color{brown}\boxed{b = 19}\)

Subsituting this in and subtracting 38 from both sides, we get: \(11x - 4ax = 19x\)

Solving, we find \(\color{brown}\boxed{a=-2}\)

BuilderBoi Apr 14, 2022

#1**0 **

Srry i dont now hw to do this but ima as buldier boy or vin to help me learn this

Kakashi Apr 14, 2022

#2**+1 **

Best Answer

Expand both equations and set them equal to each other: \(11x - 4ax + 36 = bx+2b-2\)

Subtract 2 from both sides: \(11x-4ax+38=bx+2b\)

We want them to be identical, so \(2b = 38\), and \(\color{brown}\boxed{b = 19}\)

Subsituting this in and subtracting 38 from both sides, we get: \(11x - 4ax = 19x\)

Solving, we find \(\color{brown}\boxed{a=-2}\)

BuilderBoi Apr 14, 2022