plz help

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11x-4(ax-9) is identical to b(x+2)-2

where a and b are intergers

work out the values of a and b

Guest Apr 14, 2022

+2668

+1

Best Answer

Expand both equations and set them equal to each other: $11x - 4ax + 36 = bx+2b-2$

Subtract 2 from both sides: $11x-4ax+38=bx+2b$

We want them to be identical, so $2b = 38$ , and $\color{brown}\boxed{b = 19}$

Subsituting this in and subtracting 38 from both sides, we get: $11x - 4ax = 19x$

Solving, we find $\color{brown}\boxed{a=-2}$

BuilderBoi Apr 14, 2022

BuilderBoi · Answer 1 · 2022-04-14T02:40:53

Expand both equations and set them equal to each other: $11x - 4ax + 36 = bx+2b-2$

Subtract 2 from both sides: $11x-4ax+38=bx+2b$

We want them to be identical, so $2b = 38$ , and $\color{brown}\boxed{b = 19}$

Subsituting this in and subtracting 38 from both sides, we get: $11x - 4ax = 19x$

Solving, we find $\color{brown}\boxed{a=-2}$

Kakashi · Answer 2 · 2022-04-14T02:30:11

Srry i dont now hw to do this but ima as buldier boy or vin to help me learn this