In right triangle ABC with angle B = 90˚ , we have 2sinA = 3cosA . What is sinA?

Confusedperson Jul 14, 2018

#1**+2 **

Solve for A:

2 sin(A) = 3 cos(A)

Divide both sides by cos(A):

2 tan(A) = 3

Divide both sides by 2:

tan(A) = 3/2

Take the inverse tangent of both sides:

**Arctan(3/2) =A =56.31 degrees.**

**Sin(A) = sin(56.31) =0.832**

Guest Jul 14, 2018

edited by
Guest
Jul 14, 2018