Let $ABCD$ be a trapezoid with bases $\overline{AB}$ and $\overline{CD}.$ Let $AD=5$ and $BC=7,$ and let $P$ be a point on side $\overline{CD}$ such that $\frac{CP}{PD}=\frac{7}{5}.$ Let $X,Y$ be the feet of the altitudes from $P$ to $\overline{AD},$ $\overline{BC}$ respectively. Show that $PX=PY.$
+1005 Please fix your latex and I will give you a hint on your writing problem.
Let ABCD be a trapezoid with bases AB and CD. Let AD=5 and BC=7, and let P be a point on side CD such that CP/PD=7/5. Let X and Y be the feet of altitudes from P to AD and BC respectively. Show that PX=PY
+1005 Think about the area for a triangle.
What is the formula?
This is not the official way to do it but this is the way I did it and it is correct.
