Let $ABCD$ be a trapezoid with bases $\overline{AB}$ and $\overline{CD}.$ Let $AD=5$ and $BC=7,$ and let $P$ be a point on side $\overline{CD}$ such that $\frac{CP}{PD}=\frac{7}{5}.$ Let $X,Y$ be the feet of the altitudes from $P$ to $\overline{AD},$ $\overline{BC}$ respectively. Show that $PX=PY.$

Guest Jun 19, 2020

#1

#2**0 **

Let ABCD be a trapezoid with bases AB and CD. Let AD=5 and BC=7, and let P be a point on side CD such that CP/PD=7/5. Let X and Y be the feet of altitudes from P to AD and BC respectively. Show that PX=PY

Guest Jun 19, 2020

#3**0 **

Think about the area for a triangle.

What is the formula?

This is not the official way to do it but this is the way I did it and it is correct.

hugomimihu
Jun 19, 2020