When Deb’s cat was weighed at the Vet's in June, it was 120% of its mass in March. If the cat's mass in June was 2.52 kg , what was the cat’s mass, in kilograms, in March?
Hint Example Calc
+307 Answer: \(2.1\) \(kilograms\)
Solution:
120% is the same as 6/5, so the cat has 6/5 the mass in June than what it did in March. Set the cat's mass in March to x to create the equation:
\(\frac65x=2.52\)
Multiplying both sides by 5/6 gives x = 2.1. So, Deb's cat's mass was \(2.1\) \(kilograms\) in March.
+874 \(\begin{align*} \frac{100\%}{120\%} \cdot 2.52 &= \frac{5}{6} \cdot 2.52 \\ &= 5 \cdot 0.42 \\ &= \boxed{2.1} \end{align*}\)
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