When Deb’s cat was weighed at the Vet's in June, it was 120% of its mass in March. If the cat's mass in June was 2.52 kg , what was the cat’s mass, in kilograms, in March?

Hint Example Calc

Guest Jul 15, 2021

#1**+4 **

Answer: \(2.1\) \(kilograms\)

Solution:

120% is the same as 6/5, so the cat has 6/5 the mass in June than what it did in March. Set the cat's mass in March to x to create the equation:

\(\frac65x=2.52\)

Multiplying both sides by 5/6 gives x = 2.1. So, Deb's cat's mass was \(2.1\) \(kilograms\) in March.

WhyamIdoingthis Jul 15, 2021

#2**+1 **

\(\begin{align*} \frac{100\%}{120\%} \cdot 2.52 &= \frac{5}{6} \cdot 2.52 \\ &= 5 \cdot 0.42 \\ &= \boxed{2.1} \end{align*}\)

.MathProblemSolver101 Jul 15, 2021