the coefficient of the x^4 term in the expansion of (3x+a)^6 is 59535.
work out the possible values of a .
Expanding this would give us
\(729x^6+1458ax^5+1215a^2x^4+540a^3x^3+135a^4x^2+18a^5x+a^6\)
We know that the \(x^4\) is \(59535\)
So, \(1215a^2 = 59535\)
Giving us \(a^2=49 \)
\( a=\sqrt{49},\:a=-\sqrt{49}\)
\(a=7,\:a=-7\)
-Vinculum
