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plz help!

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Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).

Sep 4, 2020

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Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).

Hello Guest!

$$x_P=x_A+\frac{2}{3}(x_B-x_A)\\ x_P=-2+\frac{2}{3}(3-(-2))$$

$$x_P=1.\overline{3}$$

$$y_P=y_A+\frac{2}{3}(y_B-y_A)\\ y_P=1+\frac{2}{3}(4-1)$$

$$y_P=3$$

The coordinates of point P are $$P\ (1.\overline{3},3)$$

!

Sep 4, 2020