Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).
+15001 Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).
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\(x_P=x_A+\frac{2}{3}(x_B-x_A)\\ x_P=-2+\frac{2}{3}(3-(-2))\)
\(x_P=1.\overline{3}\)
\(y_P=y_A+\frac{2}{3}(y_B-y_A)\\ y_P=1+\frac{2}{3}(4-1)\)
\(y_P=3\)
The coordinates of point P are \(P\ (1.\overline{3},3)\)
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