+0

# plz hep

0
36
1

The box has a height of x inches and a width of (x + 1) inches,The volume of the box is (x^3 + 8x^2 + 7x).  Find the length of the box.

Mar 9, 2021

#1
+498
+1

since the volume is height x length x width,

we can find the length by diving the volume by the width x height.

this means:
length = $$\frac{x^3 + 8^2 + 7x}{(x + 1)(x)}$$

$$= \frac{x(x^2 + 8x + 7)}{x(x + 1)}$$

$$= \frac{x^2 + 8x + 7}{x + 1}$$

$$=\frac{(x + 1)(x + 7)}{x + 1}$$

$$= (x + 7)$$

This means the length of the box is (x + 7) inches

Hope this helps :)

Mar 9, 2021