The box has a height of x inches and a width of (x + 1) inches,The volume of the box is (x^3 + 8x^2 + 7x). Find the length of the box.
+592 since the volume is height x length x width,
we can find the length by diving the volume by the width x height.
this means:
length = \(\frac{x^3 + 8^2 + 7x}{(x + 1)(x)}\)
\(= \frac{x(x^2 + 8x + 7)}{x(x + 1)}\)
\(= \frac{x^2 + 8x + 7}{x + 1}\)
\(=\frac{(x + 1)(x + 7)}{x + 1}\)
\(= (x + 7)\)
This means the length of the box is (x + 7) inches
Hope this helps :)
