\(\frac{13t^2 - 34t + 12}{3t - 2 } + 5t = 6t - 1\)

Find the largest value of t

PLZ PLZ PLZ HELP

Guest Mar 6, 2019

#1**+1 **

Mmm interesting

\(\frac{13t^2 - 34t + 12}{3t - 2 } + 5t = 6t - 1\\ \frac{13t^2 - 34t + 12}{3t - 2 } = t - 1\\ 13t^2 - 34t + 12=(t-1)(3t-2)\)

1) Now expand the right hand side

2) Take all the terms to the left hand side so the right hand side is 0

3) Solve using the quadratic formula (or any other method)

4) The answer you want is the biggest one.

Now I will leave the algebra for you.

The answer is quite simple, you can check it by plugging it into the original formula and seeing that the right hand side=left hand side.

If you get in a mess you can ask for help but be specific about what your problem is.

Have fun :)

**Please no one answer over the top of me. The detail in this answer is perfect as it is.**

Melody Mar 6, 2019