Point C is on AC such that AX=3CX. If ABC=BXA=90°, then what is BX?
[ I think this is supposed to read..."Point X is on AC such that......." ]
Triangle AXB ≈ Triangle BXC
AX/XB ≈ BX/XC
AX*XC = XB*BX
AX*CX = BX^2
(3CX)CX = BX^2
3CX^2 = BX^2
sqrt(3)CX = BX
Here's the pic :
+1836 
