\(\)Point \(P\) lies inside square \(ABCD\) such that triangle \(ABP\) is equilateral. Find \(\angle PCD\) in degrees.
Let the length of sides be 2 units.
Let E be the midpoint of DC
Let F be the midpoint of AB
Use trig to find angle C in triangle CEP
Please let guest do it from here.
hint : triangle BPC is an isosceles triangle