pol((98200-94700),(29500-28200))=

$$\Delta{x} =$$   $${\mathtt{98\,200}}{\mathtt{\,-\,}}{\mathtt{94\,700}} = {\mathtt{3\,500}}$$

\Delta{x} =

$$\Delta{y}=$$   $${\mathtt{29\,500}}{\mathtt{\,-\,}}{\mathtt{28\,200}} = {\mathtt{1\,300}}$$

\Delta{y}=

$$r=\sqrt{\Delta{x}^2+\Delta{y}^2}=$$    $${\sqrt{{{\mathtt{3\,500}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{1\,300}}}^{{\mathtt{2}}}}} = {\mathtt{3\,733.630\: \!940\: \!518\: \!893\: \!867\: \!9}}$$

r=\sqrt{\Delta{x}^2+\Delta{y}^2}=

$$\theta= \tan^{-1}{(\frac{\Delta{y}}{\Delta{x}})} =$$   $$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{1\,300}}}{{\mathtt{3\,500}}}}\right)} = {\mathtt{20.376\: \!435\: \!213\: \!836^{\circ}}}$$

\theta= \tan^{-1}{(\frac{\Delta{y}}{\Delta{x}})} =

so

$$r = 3733.63 \mbox{ units}$$

r = 3733.63  \mbox{ units}

and

$$\theta = 20.3764 \ensuremath{^\circ}$$

\theta = 20.3764 \ensuremath{^\circ}

Are you looking to turn rectangular coordinates into polar coordinates?

If so, pol(x,y) becomes (r, θ) where θ = tan^-1(y/x) and r = √(x² + y²)

However, I don't know if the values you've supplied are meant to indicate the end values of a range, or if the numbers are to be subtracted or what!