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A flagpole casts a shadow 18 ft long. At the same time, Rachael casts a shadow that is 4 ft long. If Rachael is 5 ft tall, what is the height of the flagpole?

Guest Jan 29, 2012

#1**+8 **

if you can't remember the "Intercept theorem", see the sketch how to get to the formula:

α = tan( 5ft/4ft )

α = tan( x / 18ft )

=>

tan( 5ft/4ft )=tan( x / 18ft ) |atan()

5ft/4ft=x/18ft |*18ft

x=18ft*5ft/4ft

[input]x=18ft*5ft/4ft in ft[/input]

Quote:A flagpole casts a shadow 18 ft long. At the same time, Rachael casts a shadow that is 4 ft long. If Rachael is 5 ft tall, what is the height of the flagpole?

if you can't remember the "Intercept theorem", see the sketch how to get to the formula:

α = tan( 5ft/4ft )

α = tan( x / 18ft )

=>

tan( 5ft/4ft )=tan( x / 18ft ) |atan()

5ft/4ft=x/18ft |*18ft

x=18ft*5ft/4ft

[input]x=18ft*5ft/4ft in ft[/input]

admin Jan 29, 2012

#1**+8 **

Best Answer

if you can't remember the "Intercept theorem", see the sketch how to get to the formula:

α = tan( 5ft/4ft )

α = tan( x / 18ft )

=>

tan( 5ft/4ft )=tan( x / 18ft ) |atan()

5ft/4ft=x/18ft |*18ft

x=18ft*5ft/4ft

[input]x=18ft*5ft/4ft in ft[/input]

Quote:A flagpole casts a shadow 18 ft long. At the same time, Rachael casts a shadow that is 4 ft long. If Rachael is 5 ft tall, what is the height of the flagpole?

if you can't remember the "Intercept theorem", see the sketch how to get to the formula:

α = tan( 5ft/4ft )

α = tan( x / 18ft )

=>

tan( 5ft/4ft )=tan( x / 18ft ) |atan()

5ft/4ft=x/18ft |*18ft

x=18ft*5ft/4ft

[input]x=18ft*5ft/4ft in ft[/input]

admin Jan 29, 2012