1: Let ABCDEF be a regular hexagon, and let G,H,I be the midpoints of sides AB,CD,EF respectively. If the area of triangle GHI is 225, what is the area of hexagon ABCDEF?
2: In pentagon MATHS, angle \(M \cong \angle T \cong \angle H\) and angle A is supplementary to angle S. How many degrees are in the measure of angle H?
Thanks!
1. We can generalize the true side lengths of GHI and the hexagon from the following pic, ACG
GHI will form an equilateral triangle....call the side, S
Its area = (1/2) S^2 sin ( 60) = (1/2)S^2√3/2 = √3/4S^2
So....we can find the length of one side of GHI, thusly
225 = √3/4 S^2
225 * 4 / √3 = S^2
900 / √3 = S^2
( 30 /4√3 ) = S
Look at the pic.....triangle CJB comprises 1/6 of the hexagon's area....and it is an equilateral triangle with a side of 2
And note that in the pic....its side will be (2/3) that of the true side length of triangle GHI = 20/4√3
So....the area of the hexagon is just
(6) (1/2) (20/4√3)^2 sin 60 =
3 (400/√3)√3/2 =
(3/2)*400 = 600 units^2
Second one ;
M + T + H + A + S = 540
M + T + H + A + (180-A) = 540
Since M = T = H we have that
3H + A + 180 - A = 540
3H + 180 = 540
3H = 360
H = 120°