If you made a mistake in your previos post, you are able to edit it :)
Also, I notice that you have images that have 'waiting for moderation" all over them. If this is happening for you, you can right click on the image you want to see select copy image address, and then go to a new tab in your browser and then paste your copied image address. Then you can see the image.
Hope this helps! :)
The answer to number one is 11, as the q(x) cannot cancel an exponent of 11 from p(x).
For number 2, let's find the ways to make an x^2 term. We can pair the -4x^2 and -7 together, the 2x and tx together, and then -5 and x^2 together. This gives 28 + 2t - 5 = 0, so 2t + 23 = 0 and t = -11.5.
Hoping this helped,