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Let \(P(x)\) be a nonconstant polynomial, where all the coefficients are nonnegative integers. Prove that there exist infinitely many positive integers \(n\) such that \(P(n)\) is composite.

 

For this question can someone also explain what a composite polynomial is?

 

----------Thanks! laugh

 Mar 19, 2020

Best Answer 

 #1
avatar+20802 
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A composite polynominal p(x) can be decomposed into two or more polynomials; that is, there are

polynomials u(x) and v(x) for which p(x)  =  u( v(x) ).

 Mar 19, 2020
 #1
avatar+20802 
+2
Best Answer

A composite polynominal p(x) can be decomposed into two or more polynomials; that is, there are

polynomials u(x) and v(x) for which p(x)  =  u( v(x) ).

geno3141 Mar 19, 2020
 #2
avatar+269 
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Thanks for the definition, but can you prove it too?

madyl  Mar 19, 2020

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