f(x) is a monic polynomial such that f(0)=4 and f(1)=-10. If f(x) has degree 2, what is f(x)? Express your answer in the form ax^2+bx+c, where a, b, and are real numbers.
Since f(0) = 4.....then....
c = 4
f(1) = -10 implies that
a + b + 4 = -10
a + b = -14
But a = `1
So b = -15
f (x) = x^2 - 15x + 4
