If the product (3x^2 - 5x + 4)(7 - x) can be written in the form ax^3 + bx^2 + cx + d, where a,b,c,d are real numbers, then find 8a + 4b + 2c + d.
(3x2−5x+4)(7−x)=−3x3+26x2−39x+28
a = -3, b = 26, c = -39 and d = 28
8a + 4b + 2c + d = 30
Alternatively 8a+4b+2c+d=a⋅22+b⋅22+c⋅2+d=(3⋅22−5⋅2+4)(7−2)=6⋅5=30.
+526 
