#1**0 **

Try to use polynomial division by dividing values of (x +or- \(\frac{divisors\space of \space 12}{divisors\space of \space 10}\))

im wayyyyy too lazy to do it. but eventually by trying all values you will get a quadratic. then it becomes mucchhhh easier :)

shmewy Jun 24, 2024

#2**+1 **

When we are trying to find the roots, we set q(y) to equal 0.

Thus, we have

\(12y^3-28y^2-9y+10=0\)

Factoring the polynomial, we have

\(12y^3-28y^2-9y+10=0\)

Thus, we have

\(y=\frac{1}{2},\:y=-\frac{2}{3},\:y=\frac{5}{2}\)

Thanks! :)

NotThatSmart Jun 24, 2024