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Find all roots of the polynomial
Q(y)=12y328y29y+10

 Jun 24, 2024
 #1
avatar+84 
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Try to use polynomial division by dividing values of (x +or- divisors of 12divisors of 10)

im wayyyyy too lazy to do it. but eventually by trying all values you will get a quadratic. then it becomes mucchhhh easier :)

 Jun 24, 2024
 #2
avatar+1950 
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When we are trying to find the roots, we set q(y) to equal 0. 

Thus, we have

12y328y29y+10=0

 

Factoring the polynomial, we have

12y328y29y+10=0

 

Thus, we have

y=12,y=23,y=52

 

Thanks! :)

 Jun 24, 2024
 #3
avatar+63 
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Thanks! 

MeldHunter  Jun 24, 2024

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