+0  
 
0
2
5
avatar+33 

Find all roots of the polynomial
\(Q(y) = 12y^3 - 28y^2 - 9y + 10\)

 Jun 24, 2024
 #1
avatar+85 
0

Try to use polynomial division by dividing values of (x +or- \(\frac{divisors\space of \space 12}{divisors\space of \space 10}\))

im wayyyyy too lazy to do it. but eventually by trying all values you will get a quadratic. then it becomes mucchhhh easier :)

 Jun 24, 2024
 #2
avatar+1230 
+1

When we are trying to find the roots, we set q(y) to equal 0. 

Thus, we have

\(12y^3-28y^2-9y+10=0\)

 

Factoring the polynomial, we have

\(12y^3-28y^2-9y+10=0\)

 

Thus, we have

\(y=\frac{1}{2},\:y=-\frac{2}{3},\:y=\frac{5}{2}\)

 

Thanks! :)

 Jun 24, 2024
 #3
avatar+33 
0

Thanks! 

MeldHunter  Jun 24, 2024

1 Online Users

avatar