+63 Find all roots of the polynomial
\(Q(y) = 12y^3 - 28y^2 - 9y + 10\)
+84 Try to use polynomial division by dividing values of (x +or- \(\frac{divisors\space of \space 12}{divisors\space of \space 10}\))
im wayyyyy too lazy to do it. but eventually by trying all values you will get a quadratic. then it becomes mucchhhh easier :)
+1926 When we are trying to find the roots, we set q(y) to equal 0.
Thus, we have
\(12y^3-28y^2-9y+10=0\)
Factoring the polynomial, we have
\(12y^3-28y^2-9y+10=0\)
Thus, we have
\(y=\frac{1}{2},\:y=-\frac{2}{3},\:y=\frac{5}{2}\)
Thanks! :)
