0 to the power of 0
0^0 is undefined.
its 0
its 1
nvm
i didnt see the 1st 0
\(0^0=0^{1-1}=0^1*0^{-1}=\frac{0}{0}\)
In other words, \(0^0\) is really a disguised case of \(\frac{0}{0}\), which is also undefined. Therefore, 0^0 does not have an assigned value to it.
Wait isn't x^0 always 1? That is how I was taught at least? :P
x^0 = 1 , when x ≠ 0
+2446 
