powers of 0

0^0 is undefined.

its 0

its 1

nvm

i didnt see the 1st 0

$0^0=0^{1-1}=0^1*0^{-1}=\frac{0}{0}$

In other words, $0^0$ is really a disguised case of $\frac{0}{0}$, which is also undefined. Therefore, 0^0 does not have an assigned value to it.

Wait isn't x^0 always 1? That is how I was taught at least? :P