0 to the power of 0

0^0 is undefined.

its 0

its 1

nvm

i didnt see the 1st 0

\(0^0=0^{1-1}=0^1*0^{-1}=\frac{0}{0}\)

In other words, \(0^0\) is really a disguised case of \(\frac{0}{0}\), which is also undefined. Therefore, 0^0 does not have an assigned value to it.

Wait isn't x^0 always 1? That is how I was taught at least? :P

x^0 = 1 , when x ≠ 0