+0  
 
0
1012
2
avatar

pq+12=3p+pr, and q-r=7, what is p?

Guest Feb 26, 2015

Best Answer 

 #1
avatar+27052 
+10

pq + 12 = 3p + pr

 

Subtract pr from both sides

pq - pr + 12 = 3p

 

Factor the p from the first two terms on the left-hand side

p(q-r) + 12 = 3p

 

Use the fact that q - r = 7

7p + 12 = 3p

 

Subtract 3p from both sides

4p + 12 = 0

 

Subtract 12 from both sides

4p = -12

 

Divide both sides by 4

p = -3

.

Alan  Feb 26, 2015
 #1
avatar+27052 
+10
Best Answer

pq + 12 = 3p + pr

 

Subtract pr from both sides

pq - pr + 12 = 3p

 

Factor the p from the first two terms on the left-hand side

p(q-r) + 12 = 3p

 

Use the fact that q - r = 7

7p + 12 = 3p

 

Subtract 3p from both sides

4p + 12 = 0

 

Subtract 12 from both sides

4p = -12

 

Divide both sides by 4

p = -3

.

Alan  Feb 26, 2015
 #2
avatar+20025 
+5

pq+12=3p+pr, and q-r=7, what is p ?

$$pq+12=3p+pr \quad | \quad :p \\\\
q + \frac{12}{p} = 3 + r \quad | \quad r = q-7 \\\\
\not{q} + \frac{12}{p} = 3 + \not{q}-7 \\\\
\frac{12}{p} = -4\\\\
p = -\frac{12}{4}\\\\
p = - 3$$

heureka  Feb 26, 2015

17 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.